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89 lines
2.3 KiB
Markdown
89 lines
2.3 KiB
Markdown
---
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id: 68af0687ef34c76c28ffa549
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title: "Challenge 31: Array Diff"
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challengeType: 29
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dashedName: challenge-31
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---
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# --description--
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Given two arrays with strings values, return a new array containing all the values that appear in only one of the arrays.
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- The returned array should be sorted in alphabetical order.
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# --hints--
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`array_diff(["apple", "banana"], ["apple", "banana", "cherry"])` should return `["cherry"]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(array_diff(["apple", "banana"], ["apple", "banana", "cherry"]), ["cherry"])`)
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}})
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```
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`array_diff(["apple", "banana", "cherry"], ["apple", "banana"])` should return `["cherry"]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(array_diff(["apple", "banana", "cherry"], ["apple", "banana"]), ["cherry"])`)
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}})
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```
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`array_diff(["one", "two", "three", "four", "six"], ["one", "three", "eight"])` should return `["eight", "four", "six", "two"]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(array_diff(["one", "two", "three", "four", "six"], ["one", "three", "eight"]), ["eight", "four", "six", "two"])`)
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}})
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```
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`array_diff(["two", "four", "five", "eight"], ["one", "two", "three", "four", "seven", "eight"])` should return `["five", "one", "seven", "three"]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(array_diff(["two", "four", "five", "eight"], ["one", "two", "three", "four", "seven", "eight"]), ["five", "one", "seven", "three"])`)
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}})
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```
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`array_diff(["I", "like", "freeCodeCamp"], ["I", "like", "rocks"])` should return `["freeCodeCamp", "rocks"]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(array_diff(["I", "like", "freeCodeCamp"], ["I", "like", "rocks"]), ["freeCodeCamp", "rocks"])`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def array_diff(arr1, arr2):
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return arr1
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```
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# --solutions--
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```py
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def array_diff(arr1, arr2):
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unique1 = []
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for v in arr1:
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if v not in unique1:
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unique1.append(v)
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unique2 = []
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for v in arr2:
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if v not in unique2:
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unique2.append(v)
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only1 = [v for v in unique1 if v not in unique2]
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only2 = [v for v in unique2 if v not in unique1]
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return sorted(only1 + only2)
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```
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