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74 lines
1.4 KiB
Markdown
74 lines
1.4 KiB
Markdown
---
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id: 6a22d77ddf034bc4e35b1d57
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title: "Challenge 350: Letter Distance"
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challengeType: 28
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dashedName: challenge-350
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---
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# --description--
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Given two strings of equal length, return the sum of the shortest distances between each pair of characters.
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- The input will only contain lowercase letters
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- The alphabet is treated as a circle, so the distance between `a` and `z` is 1.
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# --hints--
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`letterDistance("abc", "bcd")` should return `3`.
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```js
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assert.equal(letterDistance("abc", "bcd"), 3);
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```
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`letterDistance("abc", "xyz")` should return `9`.
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```js
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assert.equal(letterDistance("abc", "xyz"), 9);
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```
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`letterDistance("encrypt", "decrypt")` should return `10`.
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```js
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assert.equal(letterDistance("encrypt", "decrypt"), 10);
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```
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`letterDistance("algorithm", "codeblock")` should return `43`.
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```js
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assert.equal(letterDistance("algorithm", "codeblock"), 43);
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```
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`letterDistance("lobster", "penguin")` should return `47`.
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```js
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assert.equal(letterDistance("lobster", "penguin"), 47);
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```
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`letterDistance("alligator", "crocodile")` should return `55`.
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```js
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assert.equal(letterDistance("alligator", "crocodile"), 55);
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```
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# --seed--
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## --seed-contents--
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```js
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function letterDistance(str1, str2) {
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return str1;
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}
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```
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# --solutions--
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```js
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function letterDistance(str1, str2) {
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return str1.split("").reduce((sum, char, i) => {
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const diff = Math.abs(char.charCodeAt(0) - str2[i].charCodeAt(0));
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return sum + Math.min(diff, 26 - diff);
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}, 0);
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}
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```
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