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71 lines
1.4 KiB
Markdown
71 lines
1.4 KiB
Markdown
---
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id: 56105e7b514f539506016a5e
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title: Count Backwards With a For Loop
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challengeType: 1
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forumTopicId: 16808
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dashedName: count-backwards-with-a-for-loop
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---
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# --description--
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A for loop can also count backwards, so long as we can define the right conditions.
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In order to decrement by two each iteration, we'll need to change our initialization, condition, and final expression.
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We'll start at `i = 10` and loop while `i > 0`. We'll decrement `i` by 2 each loop with `i -= 2`.
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```js
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const ourArray = [];
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for (let i = 10; i > 0; i -= 2) {
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ourArray.push(i);
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}
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```
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`ourArray` will now contain `[10, 8, 6, 4, 2]`. Let's change our initialization and final expression so we can count backwards by twos to create an array of descending odd numbers.
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# --instructions--
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Push the odd numbers from 9 through 1 to `myArray` using a `for` loop.
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# --hints--
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You should be using a `for` loop for this.
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```js
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assert(/for\s*\([^)]+?\)/.test(__helpers.removeJSComments(code)));
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```
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You should be using the array method `push`.
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```js
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assert(__helpers.removeJSComments(code).match(/myArray.push/));
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```
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`myArray` should equal `[9, 7, 5, 3, 1]`.
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```js
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assert.deepEqual(myArray, [9, 7, 5, 3, 1]);
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```
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# --seed--
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## --seed-contents--
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```js
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// Setup
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const myArray = [];
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// Only change code below this line
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```
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# --solutions--
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```js
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const myArray = [];
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for (let i = 9; i > 0; i -= 2) {
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myArray.push(i);
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}
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```
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