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87 lines
1.4 KiB
Markdown
87 lines
1.4 KiB
Markdown
---
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id: 6a22d77ddf034bc4e35b1d58
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title: "Challenge 351: Pronic Number"
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challengeType: 29
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dashedName: challenge-351
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---
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# --description--
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Given a number, determine whether it is a pronic number.
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A pronic number is the product of two consecutive integers. For example, 6 is pronic because 2 * 3 = 6.
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# --hints--
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`is_pronic(6)` should return `True`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(6), True)`)
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}})
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```
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`is_pronic(15)` should return `False`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(15), False)`)
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}})
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```
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`is_pronic(12)` should return `True`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(12), True)`)
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}})
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```
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`is_pronic(132)` should return `True`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(132), True)`)
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}})
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```
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`is_pronic(80)` should return `False`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(80), False)`)
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}})
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```
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`is_pronic(0)` should return `True`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertIs(is_pronic(0), True)`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def is_pronic(n):
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return n
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```
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# --solutions--
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```py
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def is_pronic(n):
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k = int(n ** 0.5)
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return k * (k + 1) == n
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```
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