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87 lines
2.1 KiB
Markdown
87 lines
2.1 KiB
Markdown
---
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id: 698a1a73ade5ac0e19180fa2
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title: "Challenge 199: Sequential Difference"
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challengeType: 29
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dashedName: challenge-199
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---
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# --description--
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Given an array of numbers, return a new array containing the value needed to get from each number to the next number.
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- For the last number, use `0` since there is no next number.
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For example, given `[1, 2, 4, 7]`, return `[1, 2, 3, 0]`.
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# --hints--
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`find_differences([1, 2, 4, 7])` should return `[1, 2, 3, 0]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(find_differences([1, 2, 4, 7]), [1, 2, 3, 0])`)
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}})
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```
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`find_differences([10, 15, 19, 22, 24, 25])` should return `[5, 4, 3, 2, 1, 0]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(find_differences([10, 15, 19, 22, 24, 25]), [5, 4, 3, 2, 1, 0])`)
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}})
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```
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`find_differences([25, 20, 16, 13, 11, 10])` should return `[-5, -4, -3, -2, -1, 0]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(find_differences([25, 20, 16, 13, 11, 10]), [-5, -4, -3, -2, -1, 0])`)
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}})
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```
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`find_differences([0, 1, 2, 2, 3, 3, 4, 5])` should return `[1, 1, 0, 1, 0, 1, 1, 0]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(find_differences([0, 1, 2, 2, 3, 3, 4, 5]), [1, 1, 0, 1, 0, 1, 1, 0])`)
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}})
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```
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`find_differences([1, 2, 5, 12, 34, -15, -1, 41, 113, -222, -99, -40, 10, -18, -6, -2, -1])` should return `[1, 3, 7, 22, -49, 14, 42, 72, -335, 123, 59, 50, -28, 12, 4, 1, 0]`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(find_differences([1, 2, 5, 12, 34, -15, -1, 41, 113, -222, -99, -40, 10, -18, -6, -2, -1]), [1, 3, 7, 22, -49, 14, 42, 72, -335, 123, 59, 50, -28, 12, 4, 1, 0])`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def find_differences(arr):
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return arr
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```
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# --solutions--
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```py
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def find_differences(arr):
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result = []
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for i in range(len(arr)):
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if i == len(arr) - 1:
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result.append(0)
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else:
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result.append(arr[i + 1] - arr[i])
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return result
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```
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