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107 lines
2.3 KiB
Markdown
107 lines
2.3 KiB
Markdown
---
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id: 69162d64f96574d9bb629f03
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title: "Challenge 118: Date Formatter"
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challengeType: 29
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dashedName: challenge-118
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---
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# --description--
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Given a date in the format `"Month day, year"`, return the date in the format `"YYYY-MM-DD"`.
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- The given month will be the full English month name. For example: `"January"`, `"February"`, etc.
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- In the return value, pad the month and day with leading zeros if necessary to ensure two digits.
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For example, given `"December 6, 2025"`, return `"2025-12-06"`.
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# --hints--
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`format_date("December 6, 2025")` should return `"2025-12-06"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("December 6, 2025"), "2025-12-06")`)
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}})
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```
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`format_date("January 1, 2000")` should return `"2000-01-01"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("January 1, 2000"), "2000-01-01")`)
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}})
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```
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`format_date("November 11, 1111")` should return `"1111-11-11"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("November 11, 1111"), "1111-11-11")`)
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}})
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```
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`format_date("September 7, 512")` should return `"512-09-07"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("September 7, 512"), "512-09-07")`)
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}})
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```
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`format_date("May 4, 1950")` should return `"1950-05-04"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("May 4, 1950"), "1950-05-04")`)
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}})
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```
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`format_date("February 29, 1992")` should return `"1992-02-29"`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(format_date("February 29, 1992"), "1992-02-29")`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def format_date(date_string):
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return date_string
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```
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# --solutions--
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```py
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def format_date(date_string):
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months = {
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"January": "01",
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"February": "02",
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"March": "03",
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"April": "04",
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"May": "05",
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"June": "06",
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"July": "07",
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"August": "08",
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"September": "09",
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"October": "10",
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"November": "11",
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"December": "12"
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}
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month, day, year = date_string.replace(",", "").split(" ")
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day = day.zfill(2)
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return f"{year}-{months[month]}-{day}"
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```
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