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84 lines
1.5 KiB
Markdown
84 lines
1.5 KiB
Markdown
---
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id: 68ffb91507a5b645769328c6
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title: "Challenge 103: LCM"
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challengeType: 29
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dashedName: challenge-103
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---
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# --description--
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Given two integers, return the least common multiple (LCM) of the two numbers.
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The LCM of two numbers is the smallest positive integer that is a multiple of both numbers. For example, given `4` and `6`, return `12` because:
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- Multiples of `4` are `4`, `8`, `12` and so on.
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- Multiples of `6` are `6`, `12`, `18` and so on.
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- `12` is the smallest number that is a multiple of both.
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# --hints--
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`lcm(4, 6)` should return `12`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(lcm(4, 6), 12)`)
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}})
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```
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`lcm(9, 6)` should return `18`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(lcm(9, 6), 18)`)
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}})
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```
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`lcm(10, 100)` should return `100`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(lcm(10, 100), 100)`)
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}})
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```
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`lcm(13, 17)` should return `221`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(lcm(13, 17), 221)`)
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}})
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```
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`lcm(45, 70)` should return `630`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(lcm(45, 70), 630)`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def lcm(a, b):
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return a
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```
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# --solutions--
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```py
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def lcm(a, b):
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def gcd(x, y):
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return x if y == 0 else gcd(y, x % y)
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return abs(a * b) // gcd(a, b)
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```
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