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85 lines
1.6 KiB
Markdown
85 lines
1.6 KiB
Markdown
---
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id: 68cae5b538ff798bbd4da003
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title: "Challenge 65: String Count"
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challengeType: 29
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dashedName: challenge-65
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---
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# --description--
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Given two strings, determine how many times the second string appears in the first.
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- The pattern string can overlap in the first string. For example, `"aaa"` contains `"aa"` twice. The first two `a`'s and the second two.
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# --hints--
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`count('abcdefg', 'def')` should return `1`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(count('abcdefg', 'def'), 1)`)
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}})
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```
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`count('hello', 'world')` should return `0`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(count('hello', 'world'), 0)`)
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}})
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```
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`count('mississippi', 'iss')` should return `2`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(count('mississippi', 'iss'), 2)`)
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}})
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```
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`count('she sells seashells by the seashore', 'sh')` should return `3`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(count('she sells seashells by the seashore', 'sh'), 3)`)
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}})
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```
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`count('101010101010101010101', '101')` should return `10`.
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(count('101010101010101010101', '101'), 10)`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def count(text, parameter):
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return text
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```
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# --solutions--
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```py
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def count(text, pattern):
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if not pattern:
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return 0
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occurrences = 0
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for i in range(len(text) - len(pattern) + 1):
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if text[i:i+len(pattern)] == pattern:
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occurrences += 1
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return occurrences
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```
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