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97 lines
2.2 KiB
Markdown
97 lines
2.2 KiB
Markdown
---
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id: 6821ebdf237de8297eaee793
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title: "Challenge 17: Unorder of Operations"
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challengeType: 29
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dashedName: challenge-17
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---
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# --description--
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Given an array of integers and an array of string operators, apply the operations to the numbers sequentially from left-to-right. Repeat the operations as needed until all numbers are used. Return the final result.
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For example, given `[1, 2, 3, 4, 5]` and `['+', '*']`, return the result of evaluating `1 + 2 * 3 + 4 * 5` from left-to-right ignoring standard order of operations.
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- Valid operators are `+`, `-`, `*`, `/`, and `%`.
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# --hints--
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`evaluate([5, 6, 7, 8, 9], ['+', '-'])` should return `3`
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(evaluate([5, 6, 7, 8, 9], ['+', '-']), 3)`)
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}})
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```
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`evaluate([17, 61, 40, 24, 38, 14], ['+', '%'])` should return `38`
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(evaluate([17, 61, 40, 24, 38, 14], ['+', '%']), 38)`)
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}})
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```
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`evaluate([20, 2, 4, 24, 12, 3], ['*', '/'])` should return `60`
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(evaluate([20, 2, 4, 24, 12, 3], ['*', '/']), 60)`)
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}})
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```
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`evaluate([11, 4, 10, 17, 2], ['*', '*', '%'])` should return `30`
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(evaluate([11, 4, 10, 17, 2], ['*', '*', '%']), 30)`)
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}})
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```
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`evaluate([33, 11, 29, 13], ['/', '-'])` should return `-2`
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```js
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({test: () => { runPython(`
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from unittest import TestCase
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TestCase().assertEqual(evaluate([33, 11, 29, 13], ['/', '-']), -2)`)
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}})
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```
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# --seed--
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## --seed-contents--
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```py
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def evaluate(numbers, operators):
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return numbers
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```
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# --solutions--
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```py
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def do_math(a, b, operator):
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if operator == '+':
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return a + b
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elif operator == '-':
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return a - b
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elif operator == '*':
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return a * b
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elif operator == '/':
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return a / b
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else:
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return a % b
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def evaluate(numbers, operators):
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total = numbers[0]
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for i in range(1, len(numbers)):
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operator = operators[(i - 1) % len(operators)]
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total = do_math(total, numbers[i], operator)
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return total
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```
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