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90 lines
1.9 KiB
Markdown
90 lines
1.9 KiB
Markdown
---
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id: 698a1a863194f1f4e63f645e
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title: "Challenge 207: Smallest Gap"
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challengeType: 28
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dashedName: challenge-207
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---
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# --description--
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Given a string, return the substring between the two identical characters that have the smallest number of characters between them (smallest gap).
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- There will always be at least one pair of matching characters.
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- The returned substring should exclude the matching characters.
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- If two or more gaps are the same length, return the characters from the first one.
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For example, given `"ABCDAC"`, return `"DA"` because:
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- Only `"A"` and `"C"` repeat in the string.
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- The number of characters between the two `"A"` characters is 3, and between the `"C"` characters is 2.
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- So return the string between the two `"C"` characters.
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# --hints--
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`smallestGap("ABCDAC")` should return `"DA"`.
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```js
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assert.equal(smallestGap("ABCDAC"), "DA");
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```
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`smallestGap("racecar")` should return `"e"`.
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```js
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assert.equal(smallestGap("racecar"), "e");
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```
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`smallestGap("A{5e^SD*F4i!o#q6e&rkf(po8|we9+kr-2!3}=4")` should return `"#q6e&rkf(p"`.
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```js
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assert.equal(smallestGap("A{5e^SD*F4i!o#q6e&rkf(po8|we9+kr-2!3}=4"), "#q6e&rkf(p");
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```
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`smallestGap("Hello World")` should return `""`.
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```js
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assert.equal(smallestGap("Hello World"), "");
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```
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`smallestGap("The quick brown fox jumps over the lazy dog.")` should return `"fox"`.
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```js
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assert.equal(smallestGap("The quick brown fox jumps over the lazy dog."), "fox");
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```
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# --seed--
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## --seed-contents--
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```js
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function smallestGap(str) {
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return str;
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}
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```
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# --solutions--
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```js
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function smallestGap(str) {
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let minGap = Infinity;
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let result = "";
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for (let i = 0; i < str.length; i++) {
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for (let j = i + 1; j < str.length; j++) {
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if (str[i] === str[j]) {
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const gap = j - i - 1;
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if (gap < minGap) {
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minGap = gap;
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result = str.slice(i + 1, j);
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}
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break;
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}
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}
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}
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return result;
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}
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```
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