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---
id: 56533eb9ac21ba0edf2244e1
title: Nesting For Loops
challengeType: 1
forumTopicId: 18248
dashedName: nesting-for-loops
---
# --description--
If you have a multi-dimensional array, you can use the same logic as the prior waypoint to loop through both the array and any sub-arrays. Here is an example:
```js
const arr = [
[1, 2], [3, 4], [5, 6]
];
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr[i].length; j++) {
console.log(arr[i][j]);
}
}
```
This outputs each sub-element in `arr` one at a time. Note that for the inner loop, we are checking the `.length` of `arr[i]`, since `arr[i]` is itself an array.
# --instructions--
Modify function `multiplyAll` so that it returns the product of all the numbers in the sub-arrays of `arr`.
# --hints--
`multiplyAll([[1], [2], [3]])` should return `6`
```js
assert(multiplyAll([[1], [2], [3]]) === 6);
```
`multiplyAll([[1, 2], [3, 4], [5, 6, 7]])` should return `5040`
```js
assert(
multiplyAll([
[1, 2],
[3, 4],
[5, 6, 7]
]) === 5040
);
```
`multiplyAll([[5, 1], [0.2, 4, 0.5], [3, 9]])` should return `54`
```js
assert(
multiplyAll([
[5, 1],
[0.2, 4, 0.5],
[3, 9]
]) === 54
);
```
# --seed--
## --seed-contents--
```js
function multiplyAll(arr) {
let product = 1;
// Only change code below this line
// Only change code above this line
return product;
}
multiplyAll([[1, 2], [3, 4], [5, 6, 7]]);
```
# --solutions--
```js
function multiplyAll(arr) {
let product = 1;
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr[i].length; j++) {
product *= arr[i][j];
}
}
return product;
}
```