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89 lines
1.2 KiB
Markdown
89 lines
1.2 KiB
Markdown
---
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id: 56533eb9ac21ba0edf2244b1
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title: Compound Assignment With Augmented Multiplication
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challengeType: 1
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forumTopicId: 16662
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dashedName: compound-assignment-with-augmented-multiplication
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---
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# --description--
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The `*=` operator multiplies a variable by a number.
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```js
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myVar = myVar * 5;
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```
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will multiply `myVar` by `5`. This can be rewritten as:
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```js
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myVar *= 5;
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```
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# --instructions--
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Convert the assignments for `a`, `b`, and `c` to use the `*=` operator.
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# --hints--
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`a` should equal `25`.
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```js
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assert(a === 25);
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```
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`b` should equal `36`.
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```js
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assert(b === 36);
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```
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`c` should equal `46`.
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```js
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assert(c === 46);
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```
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You should use the `*=` operator for each variable.
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```js
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assert(__helpers.removeJSComments(code).match(/\*=/g).length === 3);
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```
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You should not modify the code above the specified comment.
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```js
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assert(
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/let a = 5;/.test(__helpers.removeJSComments(code)) &&
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/let b = 12;/.test(__helpers.removeJSComments(code)) &&
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/let c = 4\.6;/.test(__helpers.removeJSComments(code))
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);
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```
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# --seed--
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## --seed-contents--
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```js
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let a = 5;
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let b = 12;
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let c = 4.6;
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// Only change code below this line
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a = a * 5;
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b = 3 * b;
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c = c * 10;
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```
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# --solutions--
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```js
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let a = 5;
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let b = 12;
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let c = 4.6;
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a *= 5;
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b *= 3;
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c *= 10;
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```
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