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94 lines
2.9 KiB
Python
94 lines
2.9 KiB
Python
# Copyright 2026 Alibaba Group Holding Ltd.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""Minimal Kubernetes label selector parser for in-memory matching.
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Supports only the subset that callers in this codebase actually emit:
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- empty string ............ matches every object
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- ``key`` ................. key existence
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- ``key=value`` ........... equality (``==`` accepted as alias)
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- ``a=1,b=2`` ............. comma-joined AND of the above
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When the selector contains anything outside this grammar (set-based ops
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like ``in``, ``notin``, ``!key``), :func:`parse_selector` returns ``None``
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so the caller falls back to issuing a real Kubernetes API list request.
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"""
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from __future__ import annotations
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from typing import List, Literal, Mapping, Optional, Tuple
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Op = Literal["exists", "eq"]
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Term = Tuple[str, Op, Optional[str]]
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_LABEL_KEY_CHARS = set(
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"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789-_./"
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)
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def _is_valid_key(key: str) -> bool:
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if not key:
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return False
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return all(c in _LABEL_KEY_CHARS for c in key)
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def parse_selector(selector: str) -> Optional[List[Term]]:
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"""Parse a label selector into a list of AND terms.
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Returns ``None`` when the selector uses syntax beyond what this minimal
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parser supports. The empty selector parses to ``[]`` (match-all).
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"""
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selector = (selector or "").strip()
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if not selector:
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return []
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terms: List[Term] = []
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for raw in selector.split(","):
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clause = raw.strip()
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if not clause:
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return None
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if "==" in clause:
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key, _, value = clause.partition("==")
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elif "=" in clause:
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key, _, value = clause.partition("=")
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else:
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key, value = clause, None
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key = key.strip()
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if not _is_valid_key(key):
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return None
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if value is None:
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terms.append((key, "exists", None))
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else:
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terms.append((key, "eq", value.strip()))
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return terms
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def matches(labels: Mapping[str, str], terms: List[Term]) -> bool:
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"""Return True if ``labels`` satisfy every AND term."""
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for key, op, expected in terms:
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if op == "exists":
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if key not in labels:
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return False
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elif op == "eq":
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if labels.get(key) != expected:
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return False
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else: # pragma: no cover - exhaustive on Op
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return False
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return True
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