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1.8 KiB
1.8 KiB
id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 6a22d77ddf034bc4e35b1d57 | Challenge 350: Letter Distance | 29 | challenge-350 |
--description--
Given two strings of equal length, return the sum of the shortest distances between each pair of characters.
- The input will only contain lowercase letters
- The alphabet is treated as a circle, so the distance between
aandzis 1.
--hints--
letter_distance("abc", "bcd") should return 3.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("abc", "bcd"), 3)`)
}})
letter_distance("abc", "xyz") should return 9.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("abc", "xyz"), 9)`)
}})
letter_distance("encrypt", "decrypt") should return 10.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("encrypt", "decrypt"), 10)`)
}})
letter_distance("algorithm", "codeblock") should return 43.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("algorithm", "codeblock"), 43)`)
}})
letter_distance("lobster", "penguin") should return 47.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("lobster", "penguin"), 47)`)
}})
letter_distance("alligator", "crocodile") should return 55.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(letter_distance("alligator", "crocodile"), 55)`)
}})
--seed--
--seed-contents--
def letter_distance(str1, str2):
return str1
--solutions--
def letter_distance(str1, str2):
total = 0
for a, b in zip(str1, str2):
diff = abs(ord(a) - ord(b))
total += min(diff, 26 - diff)
return total