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id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 68ee9e3066cfd4eb2328e8a7 | Challenge 88: Weekday Finder | 29 | challenge-88 |
--description--
Given a string date in the format YYYY-MM-DD, return the day of the week.
Valid return days are:
"Sunday""Monday""Tuesday""Wednesday""Thursday""Friday""Saturday"
Be sure to ignore time zones.
--hints--
get_weekday("2025-11-06") should return Thursday.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_weekday("2025-11-06"), "Thursday")`)
}})
get_weekday("1999-12-31") should return Friday.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_weekday("1999-12-31"), "Friday")`)
}})
get_weekday("1111-11-11") should return Saturday.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_weekday("1111-11-11"), "Saturday")`)
}})
get_weekday("2112-12-21") should return Wednesday.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_weekday("2112-12-21"), "Wednesday")`)
}})
get_weekday("2345-10-01") should return Monday.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_weekday("2345-10-01"), "Monday")`)
}})
--seed--
--seed-contents--
def get_weekday(date_string):
return date_string
--solutions--
import datetime
def get_weekday(date_string):
days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
year, month, day = map(int, date_string.split("-"))
date = datetime.date(year, month, day)
return days[date.weekday() % 7 + 1 if date.weekday() != 6 else 0]