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2.4 KiB
2.4 KiB
id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 6a26df95efa55a2524399744 | Challenge 363: Bucket Fill 2 | 28 | challenge-363 |
--description--
Given a 2D grid of single-letter color strings and a target color, return the minimum number of flood fill "clicks" needed to make the entire grid the target color.
- Each click changes the clicked cell's color and the entire region of connected cells of the same color with the target color.
- Cells are connected horizontally and vertically (not diagonally).
--hints--
bucketFill([["R", "R"], ["R", "R"]], "G") should return 1.
assert.equal(bucketFill([["R", "R"], ["R", "R"]], "G"), 1);
bucketFill([["B", "B", "B"], ["B", "B", "B"], ["B", "B", "B"]], "B") should return 0.
assert.equal(bucketFill([["B", "B", "B"], ["B", "B", "B"], ["B", "B", "B"]], "B"), 0);
bucketFill([["G", "Y", "Y"], ["G", "Y", "G"], ["Y", "Y", "G"]], "R") should return 3.
assert.equal(bucketFill([["G", "Y", "Y"], ["G", "Y", "G"], ["Y", "Y", "G"]], "R"), 3);
bucketFill([["G", "G", "P", "Y"], ["O", "P", "P", "P"], ["O", "O", "P", "G"], ["G", "O", "O", "G"]], "P") should return 5.
assert.equal(bucketFill([["G", "G", "P", "Y"], ["O", "P", "P", "P"], ["O", "O", "P", "G"], ["G", "O", "O", "G"]], "P"), 5);
bucketFill([["G", "G", "C", "C", "O"], ["B", "Y", "B", "Y", "O"], ["B", "J", "O", "J", "B"], ["G", "Y", "Y", "Y", "B"], ["G", "P", "P", "G", "G"]], "Y") should return 12.
assert.equal(bucketFill([["G", "G", "C", "C", "O"], ["B", "Y", "B", "Y", "O"], ["B", "J", "O", "J", "B"], ["G", "Y", "Y", "Y", "B"], ["G", "P", "P", "G", "G"]], "Y"), 12);
--seed--
--seed-contents--
function bucketFill(grid, targetColor) {
return grid;
}
--solutions--
function bucketFill(grid, targetColor) {
const rows = grid.length;
const cols = grid[0].length;
const visited = new Set();
function dfs(r, c, color) {
const key = `${r},${c}`;
if (r < 0 || r >= rows || c < 0 || c >= cols) return;
if (visited.has(key)) return;
if (grid[r][c] !== color) return;
visited.add(key);
dfs(r + 1, c, color);
dfs(r - 1, c, color);
dfs(r, c + 1, color);
dfs(r, c - 1, color);
}
let clicks = 0;
for (let r = 0; r < rows; r++) {
for (let c = 0; c < cols; c++) {
const key = `${r},${c}`;
if (!visited.has(key) && grid[r][c] !== targetColor) {
dfs(r, c, grid[r][c]);
clicks++;
}
}
}
return clicks;
}