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id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 6a1d9f98e819ed70a0e994e0 | Challenge 334: Exact Change | 29 | challenge-334 |
--description--
Given an integer amount in cents, return the number of distinct ways to make exact change using pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents).
--hints--
exact_change(3) should return 1.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(3), 1)`)
}})
exact_change(9) should return 2.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(9), 2)`)
}})
exact_change(17) should return 6.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(17), 6)`)
}})
exact_change(39) should return 24.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(39), 24)`)
}})
exact_change(61) should return 73.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(61), 73)`)
}})
exact_change(99) should return 213.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(exact_change(99), 213)`)
}})
--seed--
--seed-contents--
def exact_change(amount):
return amount
--solutions--
def exact_change(amount):
coins = [1, 5, 10, 25]
dp = [0] * (amount + 1)
dp[0] = 1
for coin in coins:
for i in range(coin, amount + 1):
dp[i] += dp[i - coin]
return dp[amount]