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id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 698a1a73ade5ac0e19180fa8 | Challenge 205: Perfect Cube Count | 29 | challenge-205 |
--description--
Given two integers, determine how many perfect cubes exist in the range between and including the two numbers.
- The lower number is not guaranteed to be the first argument.
- A number is a perfect cube if there exists an integer (
n) wheren * n * n = number. For example, 27 is a perfect cube because3 * 3 * 3 = 27.
--hints--
count_perfect_cubes(3, 30) should return 2.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(count_perfect_cubes(3, 30), 2)`)
}})
count_perfect_cubes(1, 30) should return 3.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(count_perfect_cubes(1, 30), 3)`)
}})
count_perfect_cubes(30, 0) should return 4.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(count_perfect_cubes(30, 0), 4)`)
}})
count_perfect_cubes(-64, 64) should return 9.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(count_perfect_cubes(-64, 64), 9)`)
}})
count_perfect_cubes(9214, -8127) should return 41.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(count_perfect_cubes(9214, -8127), 41)`)
}})
--seed--
--seed-contents--
def count_perfect_cubes(a, b):
return a
--solutions--
def count_perfect_cubes(a, b):
start, end = min(a, b), max(a, b)
count = 0
n = 0
while n ** 3 <= end:
if n ** 3 >= start:
count += 1
n += 1
n = -1
while n ** 3 >= start:
if n ** 3 <= end:
count += 1
n -= 1
return count