freecodecamp--freecodecamp/curriculum/challenges/english/blocks/daily-coding-challenges-python/696655d24b614176d4c9b78d.md

id, title, challengeType, dashedName

id	title	challengeType	dashedName
696655d24b614176d4c9b78d	Challenge 170: Odd or Even Day	29	challenge-170

--description--

Given a timestamp (number of milliseconds since the Unix epoch), return:

• "odd" if the day of the month for that timestamp is odd.
• "even" if the day of the month for that timestamp is even.

For example, given 1769472000000, a timestamp for January 27th, 2026, return "odd" because the day number (27) is an odd number.

Note: The timestamp is in milliseconds and you should use the date in the UTC timezone, not in your local time.

--hints--

odd_or_even_day(1769472000000) should return "odd".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(odd_or_even_day(1769472000000), "odd")`)
}})

odd_or_even_day(1769444440000) should return "even".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(odd_or_even_day(1769444440000), "even")`)
}})

odd_or_even_day(6739456780000) should return "odd".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(odd_or_even_day(6739456780000), "odd")`)
}})

odd_or_even_day(1) should return "odd".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(odd_or_even_day(1), "odd")`)
}})

odd_or_even_day(86400000) should return "even".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(odd_or_even_day(86400000), "even")`)
}})

--seed--

--seed-contents--

def odd_or_even_day(timestamp):

    return timestamp

--solutions--

from datetime import datetime

def odd_or_even_day(timestamp):
    dt = datetime.utcfromtimestamp(timestamp / 1000)
    day = dt.day
    return "even" if day % 2 == 0 else "odd"