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2.2 KiB
id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 691b5597f0f3e85a588a5c94 | Challenge 130: Checkerboard | 29 | challenge-130 |
--description--
Given an array with two numbers, the first being the number of rows and the second being the number of columns, return a matrix (an array of arrays) filled with "X" and "O" characters of the given size.
- The characters should alternate like a checkerboard.
- The top-left cell must always be
"X".
For example, given [3, 3], return:
[
["X", "O", "X"],
["O", "X", "O"],
["X", "O", "X"]
]
--hints--
create_board([3, 3]) should return [["X", "O", "X"], ["O", "X", "O"], ["X", "O", "X"]].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(create_board([3, 3]), [["X", "O", "X"], ["O", "X", "O"], ["X", "O", "X"]])`)
}})
create_board([6, 1]) should return [["X"], ["O"], ["X"], ["O"], ["X"], ["O"]].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(create_board([6, 1]), [["X"], ["O"], ["X"], ["O"], ["X"], ["O"]])`)
}})
create_board([2, 10]) should return [["X", "O", "X", "O", "X", "O", "X", "O", "X", "O"], ["O", "X", "O", "X", "O", "X", "O", "X", "O", "X"]].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(create_board([2, 10]), [["X", "O", "X", "O", "X", "O", "X", "O", "X", "O"], ["O", "X", "O", "X", "O", "X", "O", "X", "O", "X"]])`)
}})
create_board([5, 4]) should return [["X", "O", "X", "O"], ["O", "X", "O", "X"], ["X", "O", "X", "O"], ["O", "X", "O", "X"], ["X", "O", "X", "O"]].
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(create_board([5, 4]), [["X", "O", "X", "O"], ["O", "X", "O", "X"], ["X", "O", "X", "O"], ["O", "X", "O", "X"], ["X", "O", "X", "O"]])`)
}})
--seed--
--seed-contents--
def create_board(dimensions):
return dimensions
--solutions--
def create_board(dimensions):
rows, cols = dimensions
board = []
for r in range(rows):
row = []
for c in range(cols):
row.append("X" if (r + c) % 2 == 0 else "O")
board.append(row)
return board