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id, title, challengeType, dashedName
id title challengeType dashedName
691b559495c5cb5a37b9b480 Challenge 120: Pounds to Kilograms 29 challenge-120

--description--

Given a weight in pounds as a number, return the string "(lbs) pounds equals (kgs) kilograms.".

  • Replace "(lbs)" with the input number.
  • Replace "(kgs)" with the input converted to kilograms, rounded to two decimals and always include two decimal places in the value.
  • 1 pound equals 0.453592 kilograms.
  • If the input is 1, use "pound" instead of "pounds".
  • If the converted value is 1, use "kilogram" instead of "kilograms".

--hints--

convert_to_kgs(1) should return "1 pound equals 0.45 kilograms.".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(convert_to_kgs(1), "1 pound equals 0.45 kilograms.")`)
}})

convert_to_kgs(0) should return "0 pounds equals 0.00 kilograms.".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(convert_to_kgs(0), "0 pounds equals 0.00 kilograms.")`)
}})

convert_to_kgs(100) should return "100 pounds equals 45.36 kilograms.".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(convert_to_kgs(100), "100 pounds equals 45.36 kilograms.")`)
}})

convert_to_kgs(2.5) should return "2.5 pounds equals 1.13 kilograms.".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(convert_to_kgs(2.5), "2.5 pounds equals 1.13 kilograms.")`)
}})

convert_to_kgs(2.20462) should return "2.20462 pounds equals 1.00 kilogram.".

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(convert_to_kgs(2.20462), "2.20462 pounds equals 1.00 kilogram.")`)
}})

--seed--

--seed-contents--

def convert_to_kgs(lbs):

    return lbs

--solutions--

def convert_to_kgs(lbs):
    KG_PER_POUND = 0.453592
    kgs = f"{lbs * KG_PER_POUND:.2f}"

    pound_word = "pound" if lbs == 1 else "pounds"
    kilogram_word = "kilogram" if kgs == "1.00" else "kilograms"

    return f"{lbs} {pound_word} equals {kgs} {kilogram_word}."