Files
wehub-resource-sync dde272c4b8
i18n - Build Validation / Validate i18n Builds (24) (push) Has been cancelled
CI - Node.js / Lint (24) (push) Has been cancelled
CI - Node.js / Build (24) (push) Has been cancelled
CI - Node.js / Test (24) (push) Has been cancelled
CI - Node.js / Test - Upcoming Changes (24) (push) Has been cancelled
CI - Node.js / Test - i18n (italian, 24) (push) Has been cancelled
CI - Node.js / Test - i18n (portuguese, 24) (push) Has been cancelled
CD - Docker - GHCR Images / Build and Push Images (push) Has been cancelled
chore: import upstream snapshot with attribution
2026-07-13 11:55:53 +08:00

1.6 KiB

id, title, challengeType, dashedName
id title challengeType dashedName
69162d64f96574d9bb629f02 Challenge 117: Symmetric Difference 29 challenge-117

--description--

Given two arrays, return a new array containing the symmetric difference of them.

  • The symmetric difference between two sets is the set of values that appear in either set, but not both.
  • Return the values in the order they first appear in the input arrays.

--hints--

difference([1, 2, 3], [3, 4, 5]) should return [1, 2, 4, 5].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, 2, 3], [3, 4, 5]), [1, 2, 4, 5])`)
}})

difference(["a", "b"], ["c", "b"]) should return ["a", "c"].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference(["a", "b"], ["c", "b"]), ["a", "c"])`)
}})

difference([1, "a", 2], [2, "b", "a"]) should return [1, "b"].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, "a", 2], [2, "b", "a"]), [1, "b"])`)
}})

difference([1, 3, 5, 7, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9]) should return [2, 4, 6, 8].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(difference([1, 3, 5, 7, 9], [1, 2, 3, 4, 5, 6, 7, 8, 9]), [2, 4, 6, 8])`)
}})

--seed--

--seed-contents--

def difference(arr1, arr2):

    return arr1

--solutions--

def difference(arr1, arr2):
    diff = []

    for v in arr1:
        if v not in arr2 and v not in diff:
            diff.append(v)

    for v in arr2:
        if v not in arr1 and v not in diff:
            diff.append(v)

    return diff