freecodecamp--freecodecamp/curriculum/challenges/english/blocks/daily-coding-challenges-python/68b06e589bf227324381476f.md

id, title, challengeType, dashedName

id	title	challengeType	dashedName
68b06e589bf227324381476f	Challenge 35: Word Frequency	29	challenge-35

--description--

Given a paragraph, return an array of the three most frequently occurring words.

• Words in the paragraph will be separated by spaces.
• Ignore case in the given paragraph. For example, treat Hello and hello as the same word.
• Ignore punctuation in the given paragraph. Punctuation consists of commas (,), periods (.), and exclamation points (!).
• The returned array should have all lowercase words.
• The returned array should be in descending order with the most frequently occurring word first.

--hints--

get_words("Coding in Python is fun because coding Python allows for coding in Python easily while coding") should return ["coding", "python", "in"].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_words("Coding in Python is fun because coding Python allows for coding in Python easily while coding"), ["coding", "python", "in"])`)
}})

get_words("I like coding. I like testing. I love debugging!") should return ["i", "like", "coding"].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_words("I like coding. I like testing. I love debugging!"), ["i", "like", "coding"])`)
}})

get_words("Debug, test, deploy. Debug, debug, test, deploy. Debug, test, test, deploy!") should return ["debug", "test", "deploy"].

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertEqual(get_words("Debug, test, deploy. Debug, debug, test, deploy. Debug, test, test, deploy!"), ["debug", "test", "deploy"])`)
}})

--seed--

--seed-contents--

def get_words(paragraph):

    return paragraph

--solutions--

import re
def get_words(paragraph):
    cleaned = re.sub(r'[.,?]', '', paragraph.lower())

    words = cleaned.split()

    freq = {}
    for word in words:
        freq[word] = freq.get(word, 0) + 1

    sorted_words = sorted(freq.keys(), key=lambda w: freq[w], reverse=True)

    return sorted_words[:3]