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2.1 KiB
id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 6814d8e1516e86b171929de4 | Challenge 1: Vowel Balance | 29 | challenge-1 |
--description--
Given a string, determine whether the number of vowels in the first half of the string is equal to the number of vowels in the second half.
- The string can contain any characters.
- The letters
a,e,i,o, andu, in either uppercase or lowercase, are considered vowels. - If there's an odd number of characters in the string, ignore the center character.
--hints--
is_balanced("racecar") should return True.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("racecar"), True)`)
}})
is_balanced("Lorem Ipsum") should return True.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("Lorem Ipsum"), True)`)
}})
is_balanced("Kitty Ipsum") should return False.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("Kitty Ipsum"), False)`)
}})
is_balanced("string") should return False.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("string"), False)`)
}})
is_balanced(" ") should return True.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced(" "), True)`)
}})
is_balanced("abcdefghijklmnopqrstuvwxyz") should return False.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("abcdefghijklmnopqrstuvwxyz"), False)`)
}})
is_balanced("123A#b!E&*456-o.U") should return True.
({test: () => { runPython(`
from unittest import TestCase
TestCase().assertIs(is_balanced("123A#b!E&*456-o.U"), True)`)
}})
--seed--
--seed-contents--
def is_balanced(s):
return s
--solutions--
def is_balanced(s):
vowels = set("aeiouAEIOU")
n = len(s)
half = n // 2
first_half = s[:half]
second_half = s[-half:]
def count_vowels(sub):
return sum(1 for char in sub if char in vowels)
return count_vowels(first_half) == count_vowels(second_half)