dde272c4b8
i18n - Build Validation / Validate i18n Builds (24) (push) Has been cancelled
CI - Node.js / Lint (24) (push) Has been cancelled
CI - Node.js / Build (24) (push) Has been cancelled
CI - Node.js / Test (24) (push) Has been cancelled
CI - Node.js / Test - Upcoming Changes (24) (push) Has been cancelled
CI - Node.js / Test - i18n (italian, 24) (push) Has been cancelled
CI - Node.js / Test - i18n (portuguese, 24) (push) Has been cancelled
CD - Docker - GHCR Images / Build and Push Images (push) Has been cancelled
1.4 KiB
1.4 KiB
id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 6a22d77ddf034bc4e35b1d57 | Challenge 350: Letter Distance | 28 | challenge-350 |
--description--
Given two strings of equal length, return the sum of the shortest distances between each pair of characters.
- The input will only contain lowercase letters
- The alphabet is treated as a circle, so the distance between
aandzis 1.
--hints--
letterDistance("abc", "bcd") should return 3.
assert.equal(letterDistance("abc", "bcd"), 3);
letterDistance("abc", "xyz") should return 9.
assert.equal(letterDistance("abc", "xyz"), 9);
letterDistance("encrypt", "decrypt") should return 10.
assert.equal(letterDistance("encrypt", "decrypt"), 10);
letterDistance("algorithm", "codeblock") should return 43.
assert.equal(letterDistance("algorithm", "codeblock"), 43);
letterDistance("lobster", "penguin") should return 47.
assert.equal(letterDistance("lobster", "penguin"), 47);
letterDistance("alligator", "crocodile") should return 55.
assert.equal(letterDistance("alligator", "crocodile"), 55);
--seed--
--seed-contents--
function letterDistance(str1, str2) {
return str1;
}
--solutions--
function letterDistance(str1, str2) {
return str1.split("").reduce((sum, char, i) => {
const diff = Math.abs(char.charCodeAt(0) - str2[i].charCodeAt(0));
return sum + Math.min(diff, 26 - diff);
}, 0);
}