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id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 696655d24b614176d4c9b78d | Challenge 170: Odd or Even Day | 28 | challenge-170 |
--description--
Given a timestamp (number of milliseconds since the Unix epoch), return:
"odd"if the day of the month for that timestamp is odd."even"if the day of the month for that timestamp is even.
For example, given 1769472000000, a timestamp for January 27th, 2026, return "odd" because the day number (27) is an odd number.
Note: The timestamp is in milliseconds and you should use the date in the UTC timezone, not in your local time.
--hints--
oddOrEvenDay(1769472000000) should return "odd".
assert.equal(oddOrEvenDay(1769472000000), "odd");
oddOrEvenDay(1769444440000) should return "even".
assert.equal(oddOrEvenDay(1769444440000), "even");
oddOrEvenDay(6739456780000) should return "odd".
assert.equal(oddOrEvenDay(6739456780000), "odd");
oddOrEvenDay(1) should return "odd".
assert.equal(oddOrEvenDay(1), "odd");
oddOrEvenDay(86400000) should return "even".
assert.equal(oddOrEvenDay(86400000), "even");
--seed--
--seed-contents--
function oddOrEvenDay(timestamp) {
return timestamp;
}
--solutions--
function oddOrEvenDay(timestamp) {
const date = new Date(timestamp);
const day = date.getUTCDate();
return day % 2 === 0 ? "even" : "odd";
}