chore: import upstream snapshot with attribution

curriculum/challenges/english/blocks/daily-coding-challenges-python/6a22d77ddf034bc4e35b1d57.md

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+---
+id: 6a22d77ddf034bc4e35b1d57
+title: "Challenge 350: Letter Distance"
+challengeType: 29
+dashedName: challenge-350
+---
+
+# --description--
+
+Given two strings of equal length, return the sum of the shortest distances between each pair of characters.
+
+- The input will only contain lowercase letters
+- The alphabet is treated as a circle, so the distance between `a` and `z` is 1.
+
+# --hints--
+
+`letter_distance("abc", "bcd")` should return `3`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("abc", "bcd"), 3)`)
+}})
+```
+
+`letter_distance("abc", "xyz")` should return `9`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("abc", "xyz"), 9)`)
+}})
+```
+
+`letter_distance("encrypt", "decrypt")` should return `10`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("encrypt", "decrypt"), 10)`)
+}})
+```
+
+`letter_distance("algorithm", "codeblock")` should return `43`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("algorithm", "codeblock"), 43)`)
+}})
+```
+
+`letter_distance("lobster", "penguin")` should return `47`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("lobster", "penguin"), 47)`)
+}})
+```
+
+`letter_distance("alligator", "crocodile")` should return `55`.
+
+```js
+({test: () => { runPython(`
+from unittest import TestCase
+TestCase().assertEqual(letter_distance("alligator", "crocodile"), 55)`)
+}})
+```
+
+# --seed--
+
+## --seed-contents--
+
+```py
+def letter_distance(str1, str2):
+
+    return str1
+```
+
+# --solutions--
+
+```py
+def letter_distance(str1, str2):
+    total = 0
+    for a, b in zip(str1, str2):
+        diff = abs(ord(a) - ord(b))
+        total += min(diff, 26 - diff)
+    return total
+```